Question 385882
find three consecutive odd integer, such that three times the first integer plus five times the second integer is five more than five times the third integer
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let the numbers be x,x+2,x+4
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3x+5(x+2)=5(x+4)+5
3x+5x+10=5x+20+5
8x+10=5x+25
8x-5x=25-10
3x=15
/3
x= 5
The integers are 5,7,9
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