Question 385905
Write the equation of the line perpendicular to y=4/3x-5 passing through (8,0). Write the equation in standard form Ax+By=C.
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 y=4/3x-5 passing through (8,0). 
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compare with y= mx +b
m= slope = 4/3
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slope of line perpendicular to the above line = -3/4
plug the point values and m in
y=mx+b
0=-3/4*8+b
0=-6 +b
b=6
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equation is
y=(-3/4)x +6
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multiply the equation by 4
4y=-3x+24
-3x+4y-24 =0 
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{{{graph(300,300,-10,10,-10,10,((4x/3)-5),((-3x/4)+6))}}}
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