Question 385739
x, 2x+2 are the two numbers.
Then x(2x + 2) = 40, or x(x+1) = 20, or {{{x^2 + x - 20=0}}}, or (x+5)(x-4) = 0.
Then x = -5, 4.  There are two sets of solutions: {-5, -8}, and {4, 10}.