Question 42060
for the line passing through (-4,2)and (1,-2)
a. compute the slope

slope = (change in y) / (change in x)
      = (-2 - 2) / (1 - (-4))
      = ( -4 ) / 5 = -4/5

b. find another point with integer coordinates on this line.

equation of the line is : y= mx +b
                          y = -4/5 (x) + b at point (1,-2)
                          -2 = -4/5(1) + b so b = -6/5
general formula for the line is:
y = -4/5 (x) - 6/5 --> pick a value for x say 2 so:
y = -4/5 (2) - 6/5 = -8/5 - 6/5 = -14/5
so a point would be:  (2, -14/5)


Find the equation of each line below
a. the slope of the line is -3 and it passes though the poine of (-2.6)

 y = mx + b
 y = -3x + b for point (-2, 6) b = 
 6 = -3(-2) + b
b = 0  so equation of line becomes --> y = -3x

b. the line passes through the the two points (1,-3)and (2,-1)

find slope like above:  (-1 - (-3))/(2-1) = 2
y = 2x + b  for point (2, -1) b =
-1 = 2(2) + b 
b = -5
equation then is:  y = 2x - 5

thank you. robbie