Question 385390
Let {{{n}}},{{{n+1}}}, and {{{n+2}}} be the integers.
{{{(n+n+1+n+2)/3=5}}}
{{{3n+3=15}}}
{{{3n=12}}}
{{{n=4}}}
So, the integers are 4,5 and 6.
The difference is then,
{{{D=6-4=2}}}