Question 385237
the sum of the ages of 2 computers is 8 years old. Two years ago, the older computer was three times the age the younger computer was then. What is the present ago of the older computer>
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let one be x
the other will be 8-x
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2 years ago
one computer will be x-2
second computer will be 8-x-2=6-x
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(x-2)=3(6-x)
x-2=18-3x
add +3x to both sides
x-2+3x=18-3x+3x
4x-2=18
+2    +2
4x=20
/4
x= 5 one computers age.
the other's age = 3
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m.ananth@hotmail.ca