Question 385281
the area of a rectangle is 102 square inches. the length of the rectangle is 5 inches greater than twice the width. find the dimensions of the rectangle
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width = w in
length = 2w+5 in
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L*W=Area
w(2w+5)=102
2w^2+5w=102
-102     -102
2w^2+5w-102=0
2w^2+17w-12w-102=0
w(2w+17)-6(2w+17)=0
(w-6)(2w+17)=0
w= 6 inches the width
Length=2x+5=12+5=17 inches
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