Question 385235
No, first step square both sides.
{{{x+4=4*sqrt(x+1)}}}
{{{(x+4)^2=16(x+1)}}}
{{{x^2+8x+16=16x+16}}}
{{{x^2-8x=0}}}
{{{x(x-8)=0}}}
Two solutions:
{{{highlight(x=0)}}}
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.
{{{x-8=0}}}
{{{highlight(x=8)}}}
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.
{{{drawing(300,300,-2,15,-2,15,circle(0,4,0.3),circle(8,12,0.3),grid(1),graph(300,300,-2,15,-2,15,0,x+4,4*sqrt(x+1)))}}}