Question 384799
 y varies directly as x and inversely as the square of z. 
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y = kx/z^2
Solve for "k" using the following:

y=96 when x=64 and z=4. 
96 = k*64/4^2
96 = 4k
k = 24
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Equation for this Problem:
y = 24*x/z^2
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Find y when x=75 and z=5.
y = 24*75/5^2
y = 24*3
y = 72
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Cheers,
Stan H.
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