Question 384749
A test is composed of six multiple choice questions where each question has 4 choices. If the answer choices for each question are equally likely, find the probability of answering 3 OR 4 questions correctly
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Binomial Problem with n=6 and p = 1/4
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P(3 or 4) = P(3) + P(4)
== 
6C3*(1/4)^3*(3/4)3 + 6C4*(1/4)^4*(3/4)^2
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= 0.1318 + 0.0330
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Cheers,
Stan H.