Question 384758
The equation of the line passing through the points: (3, 0) and (-1, -2) and having a slope of {{{1/2}}} in slope-intercept form:{{{y = mx+b}}} where the slope {{{m = 1/2}}}.
Start with:
{{{y = (1/2)x+b}}} since you were given the slope, m.  To find the value of b, the y-intercept, substitute the x- and y-coordinates from either one of the two given points.  Let's choose (3, 0)
{{{y = (1/2)x+b}}} Substitute x = 3 and y = 0.
{{{0 = (1/2)(3)+b}}} Simplify.
{{{0 = (3/2) + b}}} Subtract {{{3/2}}} from both sides.
{{{-(3/2) = b}}} Now substitute this into the equation above to get:
{{{y = (1/2)x-3/2}}}