Question 384763
Simplify:
{{{e^((ln(30x^5)-ln(6x^4)))}}} Simplify the exponent using the quotient rule: {{{Log[b](M)-Log[b](N) = Log[b](M/N)}}}
e^(ln(30x^5/6x^4)) Simplify the argument of the ln in the exponent.
{{{e^(ln(5x)) = 5x}}} Recall that: {{{b^(Log[b](x)) = x}}} so...
{{{e^((ln(30x^5)-ln(6x^4))) = 5x}}}