Question 384757
I presume that you want to simplify this expression!
{{{(x^9*y(-6))^(1/3)}}} Remember that: {{{y^(-n) = 1/y^n}}}so...
{{{(x^9/y^6)^(1/3)}}} Multiply the exponents inside the parentheses by the exponent on the outside to get:
{{{x^3/y^2}}}