Question 384636
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Let *[tex \Large x] represent the measure of one of the congruent angles.  Then the other congruent angle must measure *[tex \Large x] as well.  Further, the remaining angle must measure *[tex \Large 3x].  The sum of the measures of the angles of any triangle is *[tex \Large 180^\circ].  So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ x\ +\ 3x\ =\ 180]


Solve for *[tex \Large x].


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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