Question 384492
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Hi
Note: Standard Equation for an ellipse is {{{(x-h)^2/a^2 + (y-k)^2/b^2 = 1}}}
where Pt(h,k) is the center and vertices are determined by distance of a and b from center.
{{{x^2/36 + y^2/16 = 1}}} In this case:  Pt(0,0) is the Center.
Vertices (-6,0) and (6,0). (0,-4) and (0,4)
Foci: c^2 = 36-16 = 20  c = 2sqrt(5)=4.47 Foci are (4.47,0) and (4.47,0)
Minor axis is x = 0
{{{drawing(500,500, -10,10,-10,10,
 grid(1),
circle(-4.47,0,0.4),
circle(4.47,0,0.4),
graph( 500, 500,-10,10,-10,10,4*sqrt(1-.0278x^2),-4*sqrt(1-.0278x^2)))}}}