Question 384446
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Hi, 
Perimeter of a right triangle is 12 feet. (thus the sum other two sides = 9ft)       
Let 3, x  and (9ft-x) represent the lengths of the sides
Applying the Pythagoream Theorem to solve for x
 3^2 + x^2 = (9ft-x)^2
Solving for x
  9 + x^2 = 81 - 18x + x^2
      18x = 72
        x = 4ft, length of the other leg and the hypotenuse is 5ft  (9ft-4ft)
CHECKING our Answer
 3^2 + 4^2 = 9 + 16 = 25 = 5^2