Question 384323
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Hi,         
*[tex \LARGE\ \ log_4(2x-15) - log_4(x-4) = log_4(2x-15)/(x-4) = 1 ]
*[tex \LARGE \ \ \ \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
  4^1 = (2x-15)/(x-4)
  4(x-4) = 2x - 15
  4x - 16 = 2x - 15
       2x = 1
        x = 1/2