Question 42053
Hi,

Let d be the divisor and r be the remainder. We know that for some integer *[tex q_1] and *[tex q_2]

*[tex 394915=dq_2+r]

and

*[tex 391758=dq_1+r]

Subtracting these gives

*[tex 3157=d(q_2-q_1)]

We also know that d is three digits. There are only two three digit factors of 3157, and they are 287 and 451. Substituting both of them into our above equations shows that 451 is the one we're after giving a remainder of 290.

Hope that helps,
Kev