Question 384030
the present age of father is 4times of his son. 10 years before the age of father was 9times of his son age.find out their present age?
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son= x years
father = 4x
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10 years ago
son = x-10
father = 4x-10
...
4x-10=9(x-10)
4x-10=9x-90
4x-9x=-90+10
-5x=-80
/-5
x=16 son's age now
father's age = 4x = 4*16 = 64 years
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m.ananth@hotmail.ca