Question 384029
Range is (-3, {{{infinity}}}).  Y-intercept is {{{y = 4^(0+2) - 3 = 16-3 = 13}}}.  X-intercept is found by solving{{{0 = 4^(x+2)-3}}}, or {{{3= 4^(x+2)}}}.  Take ln of both sides to get: ln3 = ln4(x+2), or ln3/ln4 = x+2, or {{{x = ln3/ln4 - 2}}}.