Question 384049
{{{a(a^2-9)-2(a+3)^2}}}
={{{a(a-3)(a+3) - 2(a+3)^2}}}
={{{(a+3)(a(a-3) - 2(a+3))}}}
={{{(a+3)(a^2 - 3a - 2a-6)}}}
={{{(a+3)(a^2 - 5a- 6)}}}
={{{(a+3)(a -6)(a+1)}}}