Question 42015
This is a parabola that opens upward, and the vertex (minimum point) will be at {{{x=(-b)/(2a)}}}.  In this case, vertex is at {{{x= (8)/(2)=4}}}.


If x = 4, then y = 4^2 - 8*4 +22 = 16 - 32 +22=6.  


I get a vertex of (4, 6) .  Check it out with the graph:


{{{graph(300,300, -6,10, -4, 24, x^2-8x+22)}}}


R^2 at SCC