Question 383371
Parallel lines have identical slopes.
{{{m[1]=m[2]=-2/3}}}
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{{{y=mx+b}}}
{{{y=-(2/3)x+b}}}
Use the point (6,-2) to find {{{b}}}.
{{{-2=-(2/3)(6)+b}}}
{{{b=-2+4}}}
{{{b=2}}}
{{{highlight(y=-(2/3)x+2)}}}

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{{{drawing(300,300,-6,10,-6,10,grid(1),circle(6,-2,0.3),graph(300,300,-6,10,-6,10,-(2/3)x+2,-(2/3)x+12))}}}