Question 383391
You can use substitution.
From eq. 2,
{{{-x+(1/3)y=5}}}
{{{-3x+y=15}}}
{{{y=3x+15}}}
Substitute into eq. 1,
{{{2x+3(3x+15)=1}}}
{{{2x+9x+45=1}}}
{{{11x=-44}}}
{{{highlight(x=-4)}}}
Then from eq. 2,
{{{y=3(-4)+15}}}
{{{y=-12+15}}}
{{{highlight(y=3)}}}