Question 383331
find the equation in the form of y=mx+b through (2,2), perpendicular to y=3x+4.
 Sol'n:
  from the equation: y=3x+4, the slope(m) is already known which is 3,
for the perpendicular lines:
 (m1)(m2)= -1, where m1 and m2 are the slope of two perpendicular lines,
  if we take m1 = 3
 so, m2= -1/3
then, at pt. (2,2):
 y-y1 = m(x-x1)
 y-2=-(x-2)/3
 3(y-2)=-(x-2)
 3y-6=-x+2
 x+3y-8=0 ----answer