Question 383218
Let {{{c}}} = rate of current in mi/hr
Let {{{r}}} = rate of boat in still water
{{{r + c}}} = rate going downstream
{{{r - c}}} = rate going upstream
given:
{{{r + c = 12/2}}}
(1) {{{r + c = 6}}} mi/hr
{{{r - c = (2/3)*12 /4}}}
(2) {{{r - c = 2}}} mi/hr
add (1) and (2)
{{{2r = 8}}}
{{{r = 4}}}
and since
{{{r - c = 2}}}
{{{4 - c = 2}}}
{{{c = 2}}}
The rate of the boat in still water is 4 mi/hr
The rate of the current is 2 mi/hr