Question 383211
second leg = 2x - 1


first leg = x


hypotenuse = 2x + 1


(first leg)^2 + (second leg)^2 = (hypotenuse)^2


x^2 + (2x - 1)^2 = (2x + 1)^2


We get two answers for x: x = 0 and x = 8.


We reject x = 0 because distance must be greater than zero.


The first leg is 8^2 or 64.



The second leg is (2(8) - 1)^2 or 15^2 or 225.


The hypotenuse is (2(8) + 1)^2 = 17^2 or 289.