Question 382916
If you solve ax^2+bz+x = 0
you will get:
x = [-b +- sqrt(b^2-4ac)]/(2a)
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You get two solutions because of the +- 
in the quadratic formula.
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x = [-b + sqrt(b^2-4ac)]/(2a) and x = [-b - sqrt(b^2-4ac)]/(2a)
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Cheers,
Stan H.