Question 382879
<pre>

                 3x - 4
             __________________________
x^2 + 4x + 1 | 3x^3 +  8x^2  - 13x - 4
           -  (3x^3 + 12x^2  +  3x)
             ------------------------
                       -4x^2 - 16x - 4 
                   -  (-4x^2 - 16x - 4) 
                      -----------------
                                     0
</pre>
{{{(3x^3 +  8x^2  -13x- 4)/(x^2 + 4x + 1)= highlight((3x - 4))}}}