Question 382786
1.{{{x^2-3y^2=-1}}}
2.{{{2x^2-7y^2=-5}}}
Multipy eq. 1 by -2 and add to eq. 2,
{{{-2x^2+6y^2+2x^2-7y^2=2-5}}}
{{{-y^2=-3}}}
{{{y=0 +- sqrt(3)}}}
Then use either equation to solve for {{{x}}}.
{{{x^2-3(3)=-1}}}
{{{x^2=8}}}
{{{x=0 +- 2*sqrt(2)}}}
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{{{drawing(300,300,-4,4,-4,4,grid(1), circle(sqrt(8),sqrt(3),0.2),
circle(-sqrt(8),sqrt(3),0.2),
circle(-sqrt(8),-sqrt(3),0.2),
circle(sqrt(8),-sqrt(3),0.2),
graph(300,300,-4,4,-4,4,0,sqrt((x^2+1)/3),sqrt((2x^2+5)/7)),
graph(300,300,-4,4,-4,4,0,-sqrt((x^2+1)/3),-sqrt((2x^2+5)/7)))}}}