Question 382797
A rectangle is twice as long as it is wide and has a diagonal of length 25 cm. what are its dimensions
.
Apply Pythagorean theorem:
Let w = width
then
2w = length
.

w^2 + (2w)^2 = 25^2

w^2 + 4w^2 = 625
5w^2 = 625
w^2 = 105
w = sqrt(105)
w = 10.25 cm (width)
.
length:
2w = 2(10.25) = 20.5 cm