Question 382775
{{{ 8/(x+2)+8/(x-2)=3}}}
{{{(8x-16 + 8x+16)/(x^2 - 4) = 3}}}
{{{(16x)/(x^2 - 4) = 3}}}
{{{16x = 3x^2 - 12}}}
{{{0= 3x^2 -16x - 12}}}
(3x + 2)(x - 6) = 0.  Hence x = -2/3, 6.  None of these make the denominators equal to 0, and so they are the final answers.