Question 382735
The sum of the squares of two consecutive integers is 244. Find the two integers.
Sol'n:think it two consecutive even integers, not a consecutive integers
 let x-the first number
     x+1-the second number
 x^2+(x+2)^2 = 244
 x^2+x^2+4x+4 = 244
 2x^2+4x+4 = 244
 2x^2+4x-240=0
by quadratic formula:
 x=10 & -12
then,
if x = 10,x+2 = 12 ---answer
and
if x = -12, x+2 = -10 ----answer