Question 382710
The scores on a standardized test had mean μ = 2.818 and standard deviation σ= 1.112. A teacher had 69 students take the test. Although the students were obviously not a random sample, she considered her students to be "typical" of all the national students. What is the probability that her students achieved an average score of at least 3?
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t(3) = (3-2.818)/(1.112/sqrt(69)) = 1.3595
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P(x-bar > 3) = P(t >=1.350.089295 when df = 68) = 0.0892
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Cheers,
Stan H.