Question 382648
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You have the difference of two cubes.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^3\ -\ y^3\ =\ (x\ -\ y)(x^2\ +\ xy\ +\ y^2]


Let *[tex \Large x\ =\ 2a\ +\ b] and let *[tex \Large y\ =\ b]


Then just substitute into the pattern:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (2a\ +\ b)^3\ -\ b^3\ =\ (2a\ +\ b\ -\ b)\left((2a\ +\ b)^2\ +\ 2ab\ +\ b^2\ +\ b^2\right)]


Of course there is still a lot of simplification to do.  I'll leave that as an exercise for the student.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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