Question 382467
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 5x\ +\ 7\ =\ 0]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ =\ 1\ \ ], *[tex \LARGE b\ =\ -5\ \ ], and *[tex \LARGE c\ =\ 7]


The quadratic formula is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{-b\ \pm\ \sqrt{b^2\ -\ 4ac}}{2a}]


Just plug in the values:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{-(-5)\ \pm\ \sqrt{(-5)^2\ -\ 4(1)(7)}}{2(1)}]


And do the arithmetic.  Remember to use *[tex \Large i] when you have a negative radicand.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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