Question 382443
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Let *[tex \Large w] represent the width of the rectangle.  Then the length is represented by *[tex \Large w\ +\ 3].  The area of a rectangle is the length times the width so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ w(w\ +\ 3)\ =\ 340]


Put it in standard form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ w^2\ +\ 3w\ -\ 340\ =\ 0]


Factor and solve for *[tex \Large w].  Exclude the negative root.  Add 3 to find the length.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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