Question 382415
There are 6+3+2 = 11 candies total


There are 11 C 3 = 165 different ways to select 3 candies (where order doesn't matter)



Since there is only one way to choose 3 orange candies (3 C 3 = 1), this means that the probability is {{{1/165=0.0060606060606}}} which rounds to 0.006



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Again, there are 11 C 3 = 165 different ways to select 3 candies. 



There are 6 C 2 =  15 different ways to select 2 cherry candies and 2 C 1 = 2 different ways to select a single lemon candy.



So there are 15*2 = 30 different ways to select 2 cherries and a lemon.



So the probability is {{{30/165=2/11=0.18181818}}}