Question 382256
The terms are in x & y, but you give values for a & b ??
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simplify:log2 16y5/x7
{{{log(2,(16y^5/x^7))}}}
There's no simplification possible.  It can be rearranged.
= {{{4 + 5*log(2,y) - 7*log(2,x)}}}
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simplify:log10 x+5/2x+9 (x+5/2x+9 is under a radical
{{{log(sqrt((x+5)/(2x+9)))}}}
"Simplified" can be a matter of opinion.
= {{{(1/2)*log(x+5) - (1/2)*log(2x+9)}}}