Question 382188
{{{9^(5log(9, (x)))}}}
On the exponent, we can use the property of logarithms, {{{q*log(a, (p)) = log(a, (p^q))}}} to move the 5 into the argument as an exponent:
{{{9^(log(9,(x^5)))}}}
Since {{{log(9,(x^5))}}} represents the exponent for 9 that results in {{{x^5}}} and since {{{log(9,(x^5))}}} <i>is</i> the exponent on a 9:
{{{9^(log(9,(x^5))) = x^5}}}