Question 382005
Perpendicular lines have slopes that are negative reciprocals.
{{{m[1]*m[2]=-1}}}
{{{8*m[2]=-1}}}
{{{m[2]=-1/8}}}
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{{{y=mx+b}}}
{{{y=-(1/8)x+b}}}
Use the point (4,10) to solve for {{{b}}}.
{{{10=-(1/8)(4)+b}}}
{{{b=20/2+1/2}}}
{{{b=21/2}}}
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{{{drawing(300,300,-2,12,-2,12,grid(1),circle(4,10,0.3),graph(300,300,-2,12,-2,12,0,8x-1,-(1/8)x+21/2))}}}