Question 381821
 A rectangle is three times longer than it is wide and has a diagonal of 50. Find the dimensions of the rectangle and its perimeter.
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L = 4W
{{{50^2 = L^2 + W^2 = (4W)^2 + W^2}}}
{{{17W^2 = 2500}}}
{{{W = sqrt(2500/17)}}}
W =~ 12.12678 square units
L =~ 48.507 sq units
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Perimeter = 2L + 2W = 121.2678 units