Question 381788
{{{y=e^(-x)+5}}}
Interchange {{{x}}} and {{{y}}} and solve for the new {{{y}}}, that's the inverse.
{{{x=e^(-y)+5}}}
{{{e^(-y)=x-5
{{{-y=ln(x-5)}}}
{{{y=-ln(x-5)}}}
{{{highlight(f^(-1)=-ln(x-5))}}}