Question 381757
How do you solve 2(x+1)^2=3x+7 using the quadratic equation??
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2(x^2+2x+1) = 3x+7
4x^2+x-5 = 0
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4x^2+5x-4x-5 = 0
x(4x+5)-(4x+5) = 0
(4x+5)(x-1) = 0
x = -5/4 or x = 1
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Cheers,
Stan H.
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