Question 381697
{{{log(2,(2^(3x+1)))=log(2,(7^(x-5)))}}}
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{{{3x+1=(x-5)*log(2,(7))}}}
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{{{3x-x*log(2,(7))=-1-5*log(2,(7))}}}
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{{{x(3-log(2,(7)))=-(1+5*log(2,(7)))}}}
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{{{x=-(1+5*log(2,(7)))/(3-log(2,(7)))}}}
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{{{highlight(x=-(log(10,(2))+5*log(10,(7)))/(3*log(10,(2))-log(10,(7))))}}}