Question 381626
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Hi,         
solving for n
2n^2-7n+6=0
factoring
(2n - 3)(n -2)= 0 Note:SUM of the inner product(-3n) and the outer product(-4n) = -7n
(2n - 3)=0
   n = 3/2
(n -2)= 0
   n = 2