Question 381447
{{{N}}}, {{{N+1}}}, and {{{N+2}}} are the three consecutive integers.
{{{(N+1)(N+2)=2+10N}}}
{{{N^2+3N+N+2=10N+2}}}
{{{N^2-7N=0}}}
{{{N(N-7)=0}}}
Two solutions:
{{{highlight(N=0)}}}, then the three integers are 0,1,and 2.
.
.
.
{{{N-7=0}}}
{{{highlight_green(N=7)}}}, then the three integers are 7, 8, and 9.