Question 381573


{{{(2-x)(3+2x)}}} Start with the given expression.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(2)-x)(highlight(3)+2x)}}} Multiply the <font color="red">F</font>irst terms:{{{(2)*(3)=6}}}.



{{{(highlight(2)-x)(3+highlight(2x))}}} Multiply the <font color="red">O</font>uter terms:{{{(2)*(2*x)=4*x}}}.



{{{(2+highlight(-x))(highlight(3)+2x)}}} Multiply the <font color="red">I</font>nner terms:{{{(-x)*(3)=-3*x}}}.



{{{(2+highlight(-x))(3+highlight(2x))}}} Multiply the <font color="red">L</font>ast terms:{{{(-x)*(2*x)=-2*x^2}}}.



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So we have the terms: {{{6}}}, {{{4*x}}}, {{{-3*x}}}, {{{-2*x^2}}} 



{{{6+4*x-3*x-2*x^2}}} Now add every term listed above to make a single expression.



{{{6+x-2*x^2}}} Now combine like terms.



So {{{(2-x)(3+2x)}}} FOILs to {{{6+x-2*x^2}}}.



In other words, {{{(2-x)(3+2x)=6+x-2*x^2}}}.



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Jim