Question 381567
{{{(x-4)(x-5)}}} Start with the given expression.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(x)-4)(highlight(x)-5)}}} Multiply the <font color="red">F</font>irst terms:{{{(x)*(x)=x^2}}}.



{{{(highlight(x)-4)(x+highlight(-5))}}} Multiply the <font color="red">O</font>uter terms:{{{(x)*(-5)=-5*x}}}.



{{{(x+highlight(-4))(highlight(x)-5)}}} Multiply the <font color="red">I</font>nner terms:{{{(-4)*(x)=-4*x}}}.



{{{(x+highlight(-4))(x+highlight(-5))}}} Multiply the <font color="red">L</font>ast terms:{{{(-4)*(-5)=20}}}.



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So we have the terms: {{{x^2}}}, {{{-5*x}}}, {{{-4*x}}}, {{{20}}} 



{{{x^2-5*x-4*x+20}}} Now add every term listed above to make a single expression.



{{{x^2-9*x+20}}} Now combine like terms.



So {{{(x-4)(x-5)}}} FOILs to {{{x^2-9*x+20}}}.



In other words, {{{(x-4)(x-5)=x^2-9*x+20}}}.



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Jim