Question 381552


{{{(x+4)(x-5)}}} Start with the given expression.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(x)+4)(highlight(x)-5)}}} Multiply the <font color="red">F</font>irst terms:{{{(x)*(x)=x^2}}}.



{{{(highlight(x)+4)(x+highlight(-5))}}} Multiply the <font color="red">O</font>uter terms:{{{(x)*(-5)=-5*x}}}.



{{{(x+highlight(4))(highlight(x)-5)}}} Multiply the <font color="red">I</font>nner terms:{{{(4)*(x)=4*x}}}.



{{{(x+highlight(4))(x+highlight(-5))}}} Multiply the <font color="red">L</font>ast terms:{{{(4)*(-5)=-20}}}.



---------------------------------------------------

So we have the terms: {{{x^2}}}, {{{-5*x}}}, {{{4*x}}}, {{{-20}}} 



{{{x^2-5*x+4*x-20}}} Now add every term listed above to make a single expression.



{{{x^2-x-20}}} Now combine like terms.



So {{{(x+4)(x-5)}}} FOILs to {{{x^2-x-20}}}.



In other words, {{{(x+4)(x-5)=x^2-x-20}}}.



If you need more help, email me at <a href="mailto:jim_thompson5910@hotmail.com?Subject=Algebra%20Help">jim_thompson5910@hotmail.com</a>


Also, feel free to check out my <a href="http://www.freewebs.com/jimthompson5910/home.html">tutoring website</a>


Jim